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0.01(x^2)-x-1200=6000
We move all terms to the left:
0.01(x^2)-x-1200-(6000)=0
We add all the numbers together, and all the variables
0.01x^2-1x-7200=0
a = 0.01; b = -1; c = -7200;
Δ = b2-4ac
Δ = -12-4·0.01·(-7200)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-17}{2*0.01}=\frac{-16}{0.02} =-800 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+17}{2*0.01}=\frac{18}{0.02} =900 $
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